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MIDDLE GROUND - Normal Distributions
-- Use the Traditional Stat Table Areas as Probabilities


Traditional Stat Table Area Under the Standard Normal Curve

      Click on the table below to go to a page from which the table may be printed. Then, return to this page.

      The table, the "Cumulative Probability from the Mean to the Z-Score," states 620 intervals (310 in pink on the right and the unstated 310 on the mirror-image left), rather than the 9 stanine intervals you used on the last page.


MouseOver the arrow to see the answer.
a. What percent of scores are between 0 and .15? 5.96%
b. What percent of scores are between 0 and -.15? 5.96%
c. What percent of scores are between 0 and 2.09? 48.17%
d. What percent of scores are between 0 and -3.3? 49.88%
e. What percent of scores are greater than 1.25? 50% - 39.44% = 10.56%
f. What percent of scores are between -.75 and .25? 27.34% + 9.87% = 37.21%
g. What percent of scores are smaller than 1.25? 50% + 39.44% = 89.44%
h. What percent of scores are greater than -2.05? 50% + 47.96% = 97.96%
i. State the z-score such that 48.46% of scores are between 0 and z. 2.16 or - 2.16
 
 
Questions with Answer Page
 
1. State the area under the standard normal curve
between z-scores of 0 and 1.42.
 
2. Given the standard normal distribution, compute
p(z is within 1.42 standard deviations of the mean),
p(-1.42 < z < 1.42).
 
3. Given the standard normal distribution, find the z-score such that
p(z is within __ standard deviations of the mean) = 95%.
 
4. Find, to two decimal places accuracy, the boundaries
in the standard normal distribution, such that
p(z is within __ standard deviations of the mean) = 74.98%.
 
5. Using the z-scores in the above table, state the lowest z-score
which is in the top 90% of all scores.
 
6. Using the z-scores in the above table, state the lowest z-score
which is in the top 85% of all scores.
 
7. Compute:
p(-2.2 < z < -2.35).
 
8. Compute,
given a normal distribution, = 3 and s = 0.4,
p(2 < x < 4).
 
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