5c. There are 12 coins in a bank and the
coins have a value of $1.20.
The are five more dimes than nickels and all the rest of the coins are quarters.
Find how many dimes are in the bank.
 (nickels) + (dimes) + (quarters) = 12

 (total value) = $1.20

 .05(nickels) + .10(dimes) + .25(quarters) = $1.20

 5(nickels) + 10(five more than nickels) + 25(quarters) = 120

 5(x) + 10(5 + x) + 25(quarters) = 120

 5(x) + 10(5 + x) + 25(the rest of the 12 coins) = 120

 5(x) + 10(5 + x) + 25(12  (x + 5 + x)) = 120
 5(x) + 10(5 + x) + 25(12  2x  5) = 120
 5x + 50 + 10x + 25(12  2x  5) = 120
 15x + 50 + 25(7  2x) = 120
 15x + 50 + 175  50x = 120
 35x + 225 = 120
 35x = 105
 x=3

 x=3, and x + 5 = 8, and 12 (x + 5 + x) = 1
 The are 3 nickels, 8 dimes, and one quarter.
